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chloe ko.
christina chow.
mr. doktor's chemistry class
block g

home. mrdoktor.

Dissociation
-ionic compounds are made up of two parts
   -cation: postive charged particles
   -anion: negatively charged particles

Examples:
1. A 100 mL solution of 0.300 M NaCl is added to a 300 mL solution of 0.62 M _LiP. Determine the final concentration of each ion.
NaCl —> Na(+) + Cl(-)
C1V1 = C2V2
(0.300 M)(0.1 L) = C₂(0.5 L)
C2 = 0.12 M = [Na+] and [Cl-]

Li3P —> 3Li(+) + P(3-)
C1V1 = C2V2
(0.62 M)(0.3 L) = C2(0.5 L)
C2 = 0.372 M = [P3-]

C1V1 = C2V2
(1.86 M)(0.3 L) = C2(0.5 L)
C2 = 1.12 M = [Li+]


2. If the [Ca2+] = 0.321 M in a solution of CaCl₂ determine the solution’s concentration.
 CaCl₂ —> Ca + 2Cl
0.321 x 2/1 = 1.30 M = [Cl-]
0.321 x 1/1 = 0.321 M = [CaCl₂]

~christina :]