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chloe ko.
christina chow.
mr. doktor's chemistry class
block g

home. mrdoktor.

Diltuting SOlutions
-when two solutions are mixed the concetration changes
-dilution is the process of decreasing the concentration by adding a solvent (usually water)
-the amount of solute does not change   n₁=n ₂         n= number of moles
-because concentration is mol/L we can wrte :  C= n/v and n = Cv  SO C₁V₁ = C ₂V ₂

Examples:

Find the initial volume when 2.0M is diluted to a final volume of 300 mL with 1.2M of NaCl.
C₁V₁ = C₂V₂
(2.0M)V1 = (1.2)(0.300L)
V₁ = [(1.2M)(0.300L)/ (2.0M)
V₁ = 0.18 M


Find the concentration when 300 mL of 0.10M HCl is diluted to a final volume of 200 mL.
C₁V₁ = C₂V₂
(0.300L)(0.1M) = C₂ (0.200L)
C₂ = [(0.300L) (0.1M)] / (0.200L)
C₂ = 0.15 M

How much water must be added to 11.0 mL of 15.0 M Na₂SO4 to give a solution with a concentration of 0.40 M?
C₁V₁ = C₂V₂
(0.011L)(15.0M) = (0.40M) V₂
V₂ = (0.011L)(15.0M) / (0.40M)
V₂ = 0.413 L
413mL – 11mL = 402mL

~christina :]