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chloe ko.
christina chow.
mr. doktor's chemistry class
block g

home. mrdoktor.

-solutions are homogenous mixtures compsed of a solute and a solvent
  -solute is a chemical present in lesser amount (whatever is dissolved)
  -solvent is a chemical prsent in the greater amount (whatever does the dissolving)
-chemicals dissolved in water are aqueous
  -NaCl(aq)

Molarity
-concentration can be expressed in many different ways
  -g/L ; mL/L ; % by volume ; % by mass ; mol/L
-the most common (in chem 11 & 12) is mol/L which is also called Molarity
  -mol/L = M
  -[HCl] = concentration of HCl

molarity =mass/volume

Determine the concentrations of the solutions below:
1) 0.36 mol of water in 3.33L
    0.36mol/3.33L = 0.11mol/L
                            =0.11 M

2) 12.8g of CaS in 650mL of water [remember to convert mL to L]
12.8g x 1 mol x       1         = 0.273mol/L
             72.2g     0.650L    =0.273 M

How Many litres of solution are required tp make the following solutions?
1) 0.88mol of BeCl₂ dissolved to create a 2.2 M solution.
0.88mol x 1L      =0.4L
              2.2mol
2) 56.0g of NaI is used to create 0.654 M solution.
56.0g x 1mol    x  1L         0.571L  
           149.9g   0.654mol

~christina :]